4
3
5
6
The dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH will result in the formation of alkenes through elimination reaction. The structure of 3-bromo-3-cyclopentylhexane allows for the formation of several alkenes due to the possibility of different beta-hydrogens being removed. Let's consider the possible structures: Drawing out the different possibilities, it's apparent that there are five possible alkenes that can be formed. These include various stereoisomers (cis/trans). Therefore, there are a total of 5 alkenes possible. Hence, option C is correct.