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Question:

The two ends of a metal rod are maintained at temperatures 100°C and 110°C. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200°C and 210°C, the rate of heat flow will be?

44.0 J/s

16.8 J/s

8.0 J/s

4.0 J/s

Solution:

Heat flow is given as ΔQ/Δt = kA(dT/dx) as the temperature difference and length of rod are constant, the heat flow will be remain constant, it's value will be equal to 4 J/s, correct answer is option D.