Eduprobe
Question:
The value of ∫π/2₀ sin3x/(sinx+cosx)dx is?
π−2;4
π−2;8
π−1;4
π−1;2
Solution:
The correct option is C (π−1)/4
I=∫π/2₀sin3x/(sinx+cosx)dx
I=∫₀π/2sin3x/(sinx+cosx)dx.
π−2;4
π−2;8
π−1;4
π−1;2
The correct option is C (π−1)/4
I=∫π/2₀sin3x/(sinx+cosx)dx
I=∫₀π/2sin3x/(sinx+cosx)dx.