The variation of acceleration due to gravity g with distance d from the center of the earth is best represented by (R=Earth's radius)

With depth g1=g(1−(d)/R)
As depth d goes on increasing g1 goes on decreasing, it remains maximum at the surface of Earth. The above equation is in the form of a straight line.
With height g2=g(1−2h/R)=g−2gh/Rg2∝1/R (Hyperbola)
Acceleration due to gravity goes on decreasing as the height above Earth surface increases.
Hence the correct answer is option A.