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Question:

The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 10⁵ ms⁻¹. If a hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

Solution:

The associated wavelength is obtained from de-Broglie equation.
Here
h = 6.626 × 10⁻³⁴ kgm²s⁻¹
m = 0.1 kg
v = 4.37 × 10⁵ ms⁻¹
Substituting the above values in de broglie equation , we get
λ = h/mv = 6.626 × 10⁻³⁴ / (0.1 × 4.37 × 10⁵) = 1.516 × 10⁻³⁹ m