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Question:

The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas to the heat absorbed by it, when it undergoes a change from state A to state B, is?

13

25

23

27

Solution:

work done/heat absorbed = (nCpΔT - nCvΔT)/(nCpΔT) = 1 - (Cv/Cp) = 1 - (1/γ) = 1 - (1/5/2) = 2/5