+3 V
-3 V
+6 V
Given :I=2AUsing Kirchhoff's lawVA−I(2)−I(1)−VB=0∴VA−2I−I−VB=0OR VA−3I−VB=0Substituting I=2AVA−3(2)−VB=0VA−6−VB=0VA−VB=+6V