If two springs S1 and S2 of the force constants k1 and k2, respectively, are stretched by the same force, it is found that more work is done on spring S1 than on spring S2. Statement-1: When stretched by the same amount, work done on S1 will be more than that of S2. Statement-2: k1 < k2. Of the four choices given after the statements, choose the one that best describes the two statements.

Let the force be F. For spring S1, the work done is W1 = (1/2)k1x1^2, where x1 is the extension. For spring S2, the work done is W2 = (1/2)k2x2^2, where x2 is the extension. Given that the same force is applied, F = k1x1 = k2x2. Therefore, x1 = F/k1 and x2 = F/k2. Substituting these into the work equations, we get W1 = (1/2)k1(F/k1)^2 = F^2/(2k1) and W2 = (1/2)k2(F/k2)^2 = F^2/(2k2). Since W1 > W2, it implies F^2/(2k1) > F^2/(2k2), which simplifies to k2 > k1. Therefore, statement 2 (k1 < k2) is true. Now, let's consider statement 1. If the springs are stretched by the same amount, say x, then W1 = (1/2)k1x^2 and W2 = (1/2)k2x^2. Since k1 < k2, W1 < W2, which means statement 1 is false. Therefore, the correct option is that Statement-1 is false, and statement-2 is true.