Three different coins are tossed together. Find the probability of getting (i) exactly two heads (ii) at least two heads (iii) at least two tails

When we toss three coins simultaneously then the possible of outcomes are: HHH or HHT or HTH or THH or HTT or THT or TTH or TTT respectively; Where H is denoted for head and T is denoted for tail. Therefore, total numbers of outcome are 2³=8
(i) Exactly two heads
Favourable cases=HHT, HTH, THH
Probability of getting exactly two heads=3/8
(ii) At least two heads
Favourable cases=HHH, HHT, HTH, THH
Probability of getting at least two heads=4/8=1/2
(iii) At least two tails
Favourable cases=HTT, THT, TTH, TTT
Probability of getting at least two tails=4/8=1/2