devarshi-dt-logo

Question:

Three long wires, each carrying current i are placed parallel to each other. The distance between I and II is 3d, between II and III is 4d and between III and I is 5d. Magnetic field at side of wire II is

10µ₀i/24πd

5µ₀i/24πd

15µ₀i/24πd

20µ₀i/24πd

Solution:

According to right hand rule, magnetic field due to III will be upward and due to I, it will be horizontal leftward.Now using the standard formula for magnetic field as:M=µ₀i/2πdMagnetic field upward is:M=µ₀i/8πd(1)Magnetic field leftward is:M=µ₀i/6πd. (2)Since both the magnetic field are mutually perpendicular, so we will do the vector sum as under-root of sum of square of each term of equation 1 and 2, we get:M=5µ₀i/24πd