Three sound waves of equal amplitudes have frequencies (n-1), n, (n+1). They superimpose to give beats. The number of beats produced per second will be?
2
1
3
4
Solution:
The formula for the beat frequency is fb = f2 - f1 Where f1 and f2 are the frequencies of two waves. Now fb = f2 - f1 fb = (n+1) - (n-1) fb = (n + 1 - n + 1) fb = 2 Thus the number of beats produced per second will be 2.