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Question:

Two balls are thrown horizontally from the top of a tower with velocities v1 and v2 in opposite directions at the same time. After how much time, the angle between velocities of balls becomes 90o?

2√v1v2/g

g√v1v2

g√v1v2/2g

√v1v2/g

Solution:

General velocity vector of the projectiles is given by
→V = v1 + j(gt) .. (1)
→V = v2 + j(gt) (2)
for both the vectors above to be perpendicular, their dot product must be zero.
hence, dot product is
v1 × v2 + g²t² = 0
finally, t = √v1v2/g