Two cars moving in opposite directions approach each other with speeds of 22 m/s and 16.5 m/s respectively. The driver of the first car blows a horn having a frequency of 400 Hz. The frequency heard by the driver of the second car is [velocity of sound 340 m/s]: 448 Hz, 350 Hz, 361 Hz, 411 Hz
361Hz
411Hz
448Hz
350Hz
Solution:
The correct option is A 448Hz f1=400Hz Vs=340m/s when both source and observer are moving towards each other f2=(Vs+V2)/(Vs-V1)f1 = (340+16.5)/(340-22) x 400 = 356.5/318 x 400 ≈ 448Hz