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Question:

Two dice are thrown together. The probability of getting the same number on both dice is:

12

112

13

16

Solution:

when two dice are thrown together then total number of all possible outcomes=62=6×6=36
The favorable outcome of getting the same number on both dice is:(1,1),(2,2),(3,3),(4,4),(5,5),(6,6).
∴The number of favorable outcomes=6
∴Required probability=6/36=1/6.