Two electrons are moving with non-relativistic speeds perpendicular to each other. If corresponding de Broglie wavelengths are λ₁ and λ₂, their de Broglie wavelength in the frame of reference attached to their centre of mass is:
λCM = λ₁ = λ₂
1/λCM = 1/λ₁ + 1/λ₂
λCM = 2λ₁λ₂√λ₁² + λ₂²
λCM = (λ₁ + λ₂)/2
Solution:
Since λ = h/mv, v = h/mλ Let v₁ and v₂ are the speeds of electrons vcm = (v₁ + v₂)/2 h²/mλcm = ½(h/mλ₁ + h/mλ₂) 1/λcm = 1/λ₁ + 1/λ₂