Two lines L1: x=5, y-3-α=z-6 and L2: x=α, y-1=z-2-α are coplanar. Then α can take value(s)
1
2
3
4
Solution:
x-5=y-3-α=z-6 x-α=y-1=z-2-α will be coplanar, if the shortest distance is zero. ⇒∣∣∣∣5-α003-α6-012-α-α∣∣∣∣=0 ⇒(5-α)(α²-α+4)=0, α=1,4,5 Hence, option A and D are correct.