Eduprobe
Question:
Two π and half σ bonds are present in: N+2, N2, O+2, O2
O+2
O2
N+2
N2
Solution:
N₂⁺→B.O.=2.5→[π−Bond=2 σ−Bond=1/2]
N₂→B.O.=3.0→[π−Bond=2 σ−Bond=1]
O₂⁺=B.O.→2.5→[π−Bond=1.5 σ−Bond=1]
O₂→2→[π−Bond→1 σ−Bond=1]
O+2
O2
N+2
N2
N₂⁺→B.O.=2.5→[π−Bond=2 σ−Bond=1/2]
N₂→B.O.=3.0→[π−Bond=2 σ−Bond=1]
O₂⁺=B.O.→2.5→[π−Bond=1.5 σ−Bond=1]
O₂→2→[π−Bond→1 σ−Bond=1]