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Question:

Two short magnets of equal dipole moments M are fastened perpendicularly at their centres as given in the figure. The magnitude of the magnetic field at a distance d from the centre on the bisector of the right angle is

μ₀m4πd³

μ₀2√2M4πd³

μ₀√2M4πd³

μ₀2M4πd³

Solution:

The magnetic field at P due to horizontal magnet above its mid point
B₁=μ₀M/4πd³
The magnetic field at P due to vertical magnet above its mid point
B₂=μ₀M/4πd³
Hence the net magnetic field at point P=√B₁²+B₂²=μ₀√2M/4πd³