Cylinder P has larger linear acceleration than cylinder Q.
Both cylinders reach the ground with same translational kinetic energy.
Both cylinders P and Q reach the ground at the same time.
Cylinder Q reaches the ground with larger angular speed.
Acceleration is a = gsinθ/(1 + I/MR²)
aP = gsinθ/(1 + MR²/R²) = g/2
aQ = gsinθ (as I of Q is similar to 0)
ωp = √(2g/2l/R)
ωQ = √(2gl/R)
Thus ωp > ωQ