Two solids dissociated as follows:
A(s)⇌B(g)+C(g); Kp1=x atm²
D(s)⇌C(g)+E(g); Kp2=y atm²
The total pressure when both the solids dissociate simultaneously is:

The correct option is C
2(√x+y) atm
A(s)⇌B(g)P1+C(g)P1
D(s)⇌C(g)P2+E(g)P2
Total pressure of C, PC=P1+P2
KP1=x=PB⋅PC (1)
x=P1(P1+P2)
KP2=y=PC⋅PE (2)
y=(P1+P2)(P2)
Adding (1) and (2)
x+y=(P1+P2)²
Now total pressure PT=PC+PB+PE=(P1+P2)+P1+P2=2(P1+P2)
PT=2(√x+y).