x=±(I1d/I1−I2)
x=I2/(I1+I2)d and x=I1/(I1−I2)d
x=I1/(I1+I2)d and x=I2/(I1−I2)d
x=I1/(I1−I2)d and x=I2/(I1−I2)d
Correct option is B.
x=±(I1d/I1−I2)
Net force on wire carrying current I per unit length is μ0I1I/2πx + μ0I2I/2π(d−x) = 0
I1/x = I2/(d−x) ⇒ x = I1d/(I1−I2)