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Question:

What is the dimensions of magnetic field B in terms of C (=coulomb), M, L, T?

[M1L1T⁻²C⁻¹]

[M1L0T⁻¹C⁻¹]

[M1L0T⁻²C⁻¹]

[M1L0T⁻¹C⁻¹]

Solution:

We know that force on a particle moving perpendicular to magnetic field is F=qvB ⇒ B=F/qv
Dimension of F is [M¹L¹T⁻²]
Dimension of q is [C¹]
Dimension of v is [L¹T⁻¹]
Hence, the dimensions of B is [M¹L⁰T⁻¹C⁻¹]