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Question:

What is the force between two small charges of 2 x 10⁻⁸ C and 3 x 10⁻⁸ C placed 30 cm apart in air?

Solution:

F = (1/4πε₀)(q₁q₂/r²) = (9 x 10⁹) x (2 x 10⁻⁸)(3 x 10⁻⁸) / (0.30)² = 6 x 10⁻⁵ N