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Question:

What is the major product P in the above reaction?

CH3CH2−CH3|C|−CH3CH=CH2

CH3CH2−CH3|C=C|−CH3CH3

CH3|CH2−CH2−CH3|CH−CH=CH2

CH3−CH3|CH−CH3|CH−CH=CH2

Solution:

Due to 1,2-methyl shift, more stable tertiary cation forms and gives 2,3-dimethylpent-2-ene as major product. Therefore option D is correct.