What is the mass of the precipitate formed when 50 mL of 16.9?

The molar masses of AgNO3, NaCl, and AgCl are 169.8 g/mol, 58.5 g/mol, and 143.3 g/mol respectively. The number of moles of AgNO3 present is (50 × 16.9) / (100 × 169.8) = 0.0497. The number of moles of NaCl present is (50 × 5.8) / (100 × 58.5) = 0.0496. Thus, both AgNO3 and NaCl are present in the stoichiometric quantity. The number of moles of AgCl formed is 0.0496. The mass of AgCl formed is 0.0496 × 143.3 = 7 g. Hence, the correct option is A