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Question:

What is the maximum number of emission lines when the excited electron of H atom in n = 6 drops to the ground state?

Solution:

The maximum number of emission lines when the excited electron of a H atom in n = 6 drops to the ground state is (n₂ - n₁)(n₂ - n₁ + 1)/2 = (6 - 1)(6 - 1 + 1)/2 = 5 × 6/2 = 15 lines.