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Question:

What will be produced in a reduction reaction of methanal with H2 gas in the presence of a Pd catalyst?

C3H7OH

C4H10OH

CH3OH

C2H5OH

Solution:

Methanol is produced in a reduction reaction of methanal with H2 gas in the presence of a Pd catalyst. The reaction can be represented as follows:

HCHO + H2 --(Pd)--> CH3OH

Methanal (formaldehyde, HCHO) is reduced by hydrogen gas (H2) in the presence of a palladium (Pd) catalyst. The hydrogen adds across the carbonyl group (C=O) of methanal, converting it to a hydroxyl group (-OH), resulting in the formation of methanol (CH3OH).