2×96500 C
9650 C
96500 C
96.50 C
The oxidation reaction is as shown below.
MnO2 + e- → MnO4-
Oxidation of one mole of MnO2 requires 1 mole of electrons.
Hence, the oxidation of 0.1 mole of electrons will require 0.1 mole of electrons.
This corresponds to 96500 × 0.1 = 9650 C.