When a current of 5mA is passed through a galvanometer having a coil of resistance 15Ω, it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0-50V is:
4.005×10³Ω
2.045×10³Ω
1.985×10³Ω
2.535×10³Ω
Solution:
The correct option is B 1.985×10³Ω V=ig(Rg+Rs) 50=(5×10⁻³)(15+Rs) 15+Rs=10/5×10⁻³=2×10³ Rs=2000-15Ω Rs=1985Ω Rs=1.985kΩ Option (2) is correct.