aL²/2 + bL³/3
1/2(aL²/2 + bL³/3)
aL + bL²
1/2(aL + bL²)
The work done in stretching the rubber band is given by the integral of the force over the distance stretched. The force is given by F = ax + bx².
The work done (W) is:
W = ∫₀ˡ F dx = ∫₀ˡ (ax + bx²) dx
Integrating, we get:
W = [ax²/2 + bx³/3]₀ˡ
W = (aL²/2 + bL³/3) - (a(0)²/2 + b(0)³/3)
W = aL²/2 + bL³/3