When capacitor is fully charged, find current drawn from the cell.
2mA
1mA
3 mA
9 mA
Solution:
Correct option is C. 3 mA When the capacitor C is fully charged, then it becomes open. Hence Equivalent resistance , R = (2+1)kΩ = 3kΩ Hence Current drawn form the cell , I = V/R = 9/(3×10³) = 3×10⁻³ = 3mA