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Question:

When the energy of the incident radiation is increased?

1.5 eV

0.65 eV

1.0 eV

1.3 eV

Solution:

From photoelectric equation, KEmax = hv - φ
0.5eV = hv - φ (1)
0.8eV = 1.2hv - φ (2)
Solving equations (1) and (2), we get φ = 1eV