[RhCl(CO)(PPh3)(NH3)]
[Fe(C2O4)3]3-
[Fe(en)2Cl2]
[Pd(en)2Cl2]
Correct option is A. [RhCl(CO)(PPh3)(NH3)]
Solution:- (A) [RhCl(CO)(PPh3)(NH3)]
[RhCl(CO)(PPh3)(NH3)] is a square planar complex and thus is inactive. It has a molecular plane of symmetry so it is optically inactive.