λ°Al³⁺ + λ°SO₄²⁻
13λ°Al³⁺ + 12λ°SO₄²⁻
2λ°Al³⁺ + 3λ°SO₄²⁻
(λ°Al³⁺ + λ°SO₄²⁻) x 6
At infinite dilution, when dissociation is complete, each ion makes a definite contribution towards the molar conductance of the electrolyte irrespective of the nature of the other ion with which it is associated. The equivalent conductance at infinite dilution is given by the sum of the equivalent conductances of the individual ions. Al₂(SO₄)₃ dissociates as follows:
Al₂(SO₄)₃ → 2Al³⁺ + 3SO₄²⁻
The equivalent conductance at infinite dilution (Λ°) for Al₂(SO₄)₃ is given by:
Λ° = (2 × Equivalent conductance of Al³⁺) + (3 × Equivalent conductance of SO₄²⁻) = 2λ°Al³⁺ + 3λ°SO₄²⁻
Therefore, the correct expression is 2λ°Al³⁺ + 3λ°SO₄²⁻.