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Question:

Which of the following is diamagnetic?

[NiCl4]2-

[PtCl4]2-

[Cu(NH3)4]2+

[Cu(H2O)4]2+

Solution:

[Cu(NH3)4]2+ No. of unpaired electrons = 1 So, [Cu(NH3)4]2+ is paramagnetic. No. of unpaired electrons = 2 So, [NiCl4]2- is paramagnetic. No. of unpaired electrons = 0 So, [PtCl4]2- is diamagnetic. No. of unpaired electrons = 1 So, [Cu(H2O)4]2+ is paramagnetic.