1−d,2−e,3−b,4−a
1−e,2−b,3−c,4−d
1−b,2−a,3−e,4−d
1−c,2−d,3−a,4−b
We can write cosθ as 1
1/cosθ = 1/secθ ∴ cosθ = 1/secθ. (1)
Now, tanθ = sinθ/cosθ = 1/cosθ/sinθ = 1/cotθ ∴ tanθ = 1/cotθ (2)
cotθ = 1/tanθ (3)
sinθ = 1
1/sinθ = 1/cosecθ. (4)
Hence, the correct answer is 1−c,2−d,3−a,4−b