XeF2+PF5→[XeF]++PF6−
XeF4+O2F2→XeF6+O2
XeF6+2H2O→XeO2F2+4HF
XeF6+H2O→XeOF4+2HF
The reaction XeF4+O2F2→XeF6+O2 is an example of a redox reaction. The oxidation number of Xe increases from +4 (XeF4) to +6 (XeF6). Hence, it is oxidised. The oxidation number of oxygen decreases from +1 (O2F2) to 0 (O2). Hence, it is reduced. Hence, the option (B) is the correct answer.