XeO3+6HF⟶XeF6+3H2O
3XeF4+6H2O⟶2Xe+XeO3+12HF+1.5O2
2XeF2+2H2O⟶2Xe+4HF+O2
XeF6+RbF⟶Rb[XeF7]
XeO3+6HF⟶XeF6+3H2O This reaction is not feasible because the products again react to give reactants back. All the xenon fluorides easily undergo hydrolysis and give xenon oxides. Hence, option D is correct.