Which of the following values of α satisfy the equation ||| (1+α)²(1+2α)²(1+3α)²(2+α)²(2+2α)²(2+3α)²(3+α)²(3+2α)²(3+3α)² ||| = 48α?

||| (1+α)²(1+2α)²(1+3α)²(2+α)²(2+2α)²(2+3α)²(3+α)²(3+2α)²(3+3α)² |||C3→C3−C2 and C2→C2−C1, above determinant reduces to:
→α||| (1+α)²2+3α2+5α(2+α)²4+3α4+5α(3+α)²6+3α6+5α |||C3→C3−C2,
→α||| (1+α)²2+3α2α(2+α)²4+3α2α(3+α)²6+3α2α |||
→2α²||| (1+α)²2+3α1(2+α)²4+3α1(3+α)²6+3α1 |||R1→R1−R2 and R2→R2−R3,
→2α²||| (1+α)²2+3α0(2+α)²4+3α0(3+α)²6+3α1 |||=48α³ →48α³=48α, which gives α=±9