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Question:

Which one of the following biomolecules is correctly characterised?

Adenylic acid - adenosine with a glucose phosphate molecule.

Alanine amino acid - Contains an amino group and an acidic group anywhere in the molecule.

Palmitic acid - an unsaturated fatty acid with 18 carbon atoms.

Lecithin - a phosphorylated glycerine found in cell membrane.

Solution:

Palmitic acid is a saturated fatty acid. It is mainly found in animals, plants, and microorganisms. Its chemical formula is CH3(CH2)14COOH. Adenosine monophosphate (AMP), also known as 5'-adenylic acid, is a nucleotide. It is used as a monomer in DNA and RNA. It is an ester of phosphoric acid and the nucleoside adenosine. AMP consists of a phosphate group, the sugar ribose, and the nucleobase adenine. Alanine is an α-amino acid with the chemical formula CH3CH(NH2)COOH. The L-isomer is one of the 20 amino acids encoded by the genetic code. Its codons are GCU, GCC, GCA, and GCG. It is classified as a non-polar amino acid. Lecithin is the major component of the phospholipid portion of the cell membrane. Thus, option D is correct and other options are wrong. So, the correct answer is option D.