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Question:

Which term of the A.P. 8, 14, 20, 26... will be 72 more than its 41st term?

Solution:

AP:8,14,20,26...a=8d=14𕒼=6LetTn=T41+72a+(n𕒵)d=a+40d+72⇒a+(n𕒵)d−a󔼰d=72⇒d(n𕒵󔼰)=72⇒6(n󔼱)=72⇒n󔼱=12⇒n=12+41∴n=53Required term = 5353thterm of AP will be 72 more than its41thterm