devarshi-dt-logo

Question:

Write a Pythagorean triplet whose one number is: (i) 6 (ii) 14 (iii) 16 (iv) 18

Solution:

2m, m^2+1, m^2-1; form a Pythagorean triplet for any number
(i) 2m = 6 ⇒ m = 3
So, Pythagorean triplets are 6, 10, 8
(ii) 2m = 14 ⇒ m = 7
So, Pythagorean triplets are 7, 48, 50
(iii) 2m = 16 ⇒ m = 8
So, Pythagorean triplets are 16, 63, 65
(iv) 2m = 18 ⇒ m = 9
So, Pythagorean triplets are 18, 80, 82