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Question:

Write first four terms of the AP, when the first term a and the common difference d are given as follows:
(i) a=10, d=10
(ii) a=-2, d=0
(iii) a=4, d=-3
(iv) a=-1, d=12
(v) a=-1.25, d=-0.25

Solution:

An arithmetic progression is given bya,(a+d),(a+2d),(a+3d), .wherea=the first term,d=the common difference(i)10,10+10,10+2(10)and10+3(10)=10,20,30and40(ii)−2;,−2;+(0),−2;+2(0)and−2;+3(0)=−2;,−2;,−2;and−2;(this is not an A.P)(iii)4,4+(−3),4+2(−3)and4+3(−3)=4,4−3,4−6;and4−9=4,1,−2;and−5(iv)−1;,−1;+(12),−1;+2(12)and−1;+3(12)=−1;,−1;2,0and12(v)−1;.25,−1;.25+(−0.25),−1;.25+2(−0.25)and−1;.25+3(−0.25)=−1;.25,−1;.50,−1;.75and−2;.0