Eduprobe
Question:
Write the anti-derivative of (3√x + 1/√x)
Solution:
Antiderivative of 3√x + 1/√x is ∫(3√x + 1/√x)
We get ∫3√x + ∫1/√x = 2x³/² + 2√x = 2√x(x+1)
Antiderivative of 3√x + 1/√x is ∫(3√x + 1/√x)
We get ∫3√x + ∫1/√x = 2x³/² + 2√x = 2√x(x+1)