Write the expression for the Broglie wavelength associated with a charged particle having charge 'q' and mass 'm', when it is accelerated by a potential V.

When the charge particle is accelerated by a potential V, the kinetic energy is equal to electrostatic potential energy. Thus, 1/2mv²=qV or v=√(2qV/m) Hence, the de Broglie wavelength, λ=h/p=h/mv=h√(2mqV)