(i) When propanal reacts with excess of methanol in the presence of HCl, it forms 1,1-dimethoxy propane.
C2H5−CHO + 2CH3OH →HCl C2H5−CH(OCH3)2 (1,1−dimethoxy propane)
(ii) Propanal having α-hydrogen atom undergo aldol condensation in presence of dil. NaOH and forms 3-hydroxy-2-methyl pentanal.
C2H5−CHO + NaOH(dilute) → C2H5−CHOH−CHCH3−CHO
(iii) The carbonyl group of propanal is reduced to CH2 group on treatment with hydrazine followed by heating with KOH in ethylene glycol and the product formed will be propane.
C2H5−CHO → −H2ONH2−NH2 C2H5−CNH−NH2 →heat KOH/ethylene glycol C2H5−CH3 + N2