Since (î × ĵ) = k̂Now consider (î × ĵ) ⋅ k̂ + î ⋅ ĵ as shown below:(î × ĵ) ⋅ k̂ + î ⋅ ĵ = k̂ ⋅ k̂ + î ⋅ ĵ = 1 + 0 = 1Hence, (î × ĵ) ⋅ k̂ + î ⋅ ĵ = 1.