Eduprobe
Question:
Write the value of (k × i) · j + i · k
Solution:
Since (k × i) = j
Now consider (k × i) · j + i · k as shown below:
(k × i) · j + i · k = j · j + i · k = 1 + 0 = 1
Hence, (k × i) · j + i · k = 1.
Since (k × i) = j
Now consider (k × i) · j + i · k as shown below:
(k × i) · j + i · k = j · j + i · k = 1 + 0 = 1
Hence, (k × i) · j + i · k = 1.